Tuesday, April 16, 2013

Glomerular Filtration Rate

GFR

Filtration barrier

3 layers

  • endothelium
  • basement membrane - negative charge 
  • epithelial cells with slit pores
Ultrafiltrate Composition

  • Large proteins and cells excluded at endothelium.
  • Electrolytes and small molecules are filtered.
  • Negatively charged barrier inhibits filtration of negatively charged substances.
  • Filtrate formed at rate of 100 to 140 ml/min
  • Filtrate = Plasma - Proteins (and proteinbound substances)
  • • Filtrate volume average 125 ml/min, 180 l/day.
  • • 99% filtrate reabsorbed

GFR = Starling Equation



Filtration Coefficient (Kf)
• Measure of permeability of membrane
• Normal value = 12.5 ml/min/mmHg
• Mesangial cells can regulate Kf
• Hormones and disease can alter Kf including mutations of nephrin
• Mesangial cell contraction decreases Kf
• Oncotic pressure in BS normally = zero
GFR = Kf[(PGC - PBS) - (piGC)


GFR Regulation

  • AT2 - low dose increases GFR (efferent arteriole constricts) - high dose decreases GFR by decreasing Kf)
  • Renin 
  • Glomerular tubular balance - filtrate reabsorbed (follows Na) at proximal tubule (passive)
Clearance

simplified = mass balance
  • amount of substance into kidney = amount out of kidney.  amount of any substance = concentration x volume (C x V)
  • one way into kidney (renal artery)
  • two ways out of kidney (renal vein and urine)
  • If substance is filtered freely but not secreted  or reabsorbed, then amount filtered = amount in urine.
    • Cp x Vp = Cu x  Vu   rearrange of Vp 
    • Vp = (Cu x Vu)/Cp
    • Vp = GFR
    • creatinine and inulin obey the rules
    • for creatinine Cp x Vp = Cu x  Vu  = 1 mg/dL x 125 ml/min = 125 mg/dL x 1 ml/min  ---- note that creatine is concentrated 125 fold and H2O is conserved.
  • Clearance of creatinine = GFR
  • clearance of PAH = renal plasma flow (RPF)  (PAH filtered and completely secreted, so amount in urine = amount of renal artery plasma flow)

Body Fluid Compartments

  • 60 - 40 - 20 rule
  • measure using dilution of substances "trapped" in a compartment
    • AMOUNT = C x V    so V = Amt/C
Plasma osmolality = 2 x PNa + [glucose]/18 + BUN/2.8
• Protein is ignored since it usually contributes less than 1 mOsm
• [glucose] is divided by 18 and BUN by 2.8 to convert from mg/dL to mmol/L
• PNa is multiplied by 2 to account for the accompanying anion (usually Cl- or HCO3-)
• 2 x PNa gives an estimate of plasma osmolality • (will give a low value if glucose, BUN or organic acids are elevated.)

isotonic versus isosmotic clarification

  • isotonic = solution in which cell size doesn't change  
  • isosmotic = solutions with same number of particles
  • Two solutions are isosmotic when they have the same number of dissolved particles, 
    regardless of how much water would flow across a given membrane barrier. In contrast, 
    two solutions are isotonic when they would cause no water movement across a 
    membrane barrier, regardless of how many particles are dissolved.

    In the example given above, a 150 mM NaCl solution would be isosmotic to the
     inside of a cell, and it would also be isotonic--the cell would not swell or shrink 
    when placed in this solution (cell is normally ~300 mM). On the other hand, 
    a 300 mM urea solution, while still isosmotic would cause the cell to swell 
    and burst (due to its permeability). This isosmotic urea solution is not isotonic. 
    Instead it has a lower tonicity (hypotonic).
  • http://www.flashcardmachine.com/membrane-transport-.html

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